This function accepts number format year as a parameter and returns true if year is a leap year else it returns false.
Function
function isLeapYear($year) { if (($year % 4) != 0){ return false; } if ($year % 400 == 0) { return true; } else if (($year > 1582) and ($year % 100 == 0)) { return false; } }
Calling The function
echo isLeapYear(2000);
Output
1
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